idk
11% without
39% with
if you have 8 marbles in the bag (5 blue and 3 green) and you draw 2 with replacement, what is the theoretical probability that both marbles wil be green
how does the probability of getting two greens change if you are not replacing??
if you have 8 marbles in the bag (5 blue and 3 green) and you draw 2 without replacement, what is the theoretical probability that both marbles will be green
if you have 8 marbles in the bag (5 blue and 3 green) and you draw 2 with replacement, what is the theoretical probability that both marbles will be green
2 answers
with replacement:
prob(2 green) = (3/8)(3/8) = 9/64
without replacement
prob(2 green) = (3/8)(2/7) = 6/56 = 3/28
prob(2 green) = (3/8)(3/8) = 9/64
without replacement
prob(2 green) = (3/8)(2/7) = 6/56 = 3/28
6 answers