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If you had this complex ion [CoCo3(NH3)4]^+, where the CO3^-2 is a bidentate ligand. what is the oxidation state of the cobalt and would this complex ion be octahedral or square planar.

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CO3^-2 is -2, NH3 is neutral, and the ion has a +1 charge on it. Therefore, Co must be +3 to add to -2 and leave a +1 on the ion. Right? I see a coordination number of 6 (4+2) so I would think octahedral. Square planar would be from a coordination number of +4. (+4 also gives tetrahedral).
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