wrong formula
D=InitialVelocity*time+ 1/2 a t^2
a= acceleration due to gravity, 9.8m/s^2
initial veloicty is zero if you drop it.
If you drop a golf ball, how far does it fall in 0.5s?
Is the correct formula to use?:
D = V1 + t + 1/2at^2. But the problem is that I don't know the acceleration, would that be 0?
3 answers
Let u=0 and a=g=9.8m/s^2 and t=0.5s.
Use: d=ut+1/2at^2
d=1/2at^2
d=4.9*(0.5)^2
d=1.2m in 1.d.p
Use: d=ut+1/2at^2
d=1/2at^2
d=4.9*(0.5)^2
d=1.2m in 1.d.p
Hi