If you are told the mean grade in ECON 2023 is 80 with a standard deviation of 5, what is the probability that if you randomly selected 36 students you would find an average grade of 82 or more?

Question

I found the Z-score: 82-80/5
Which gave me .6554 then 1-.6554=.3446

So 34% would make a 82 or more

Answer 1

You are looking for a distribution of means rather than raw scores.

Z = (score-mean)/SEm

SEm = SD/√n

Now go to your Z table.