max height when t = -b/2a. That is, when t=2
Solve for t when h=0 to find when it hits the ground.
So, where is the ball when t=0? That is, where does it start?
) If you are standing near the edge of the top of a 200 ft. building and throw a ball
vertically upward it will be modeled by the function 𝑠(𝑡) = −16𝑡2 + 64𝑡 + 200 where
s(t) is the balls height above ground in feet and t is seconds after the ball was
thrown.
a. Graph the quadratic function
b. When does the ball reach its maximum height?
c. What is the maximum height?
d. When does the ball hit the ground? (round to the nearest tenth of a second)
e. Find s(0) and describe what it represents.
1 answer