If you are standing near the edge of the top of a 200 feet building and throw a ball vertically upward it will be modeled by the function s(t)=-16t^2+64t+200 where s(t) is the ball's height above ground in feet and t is seconds after the ball was thrown.

Question

If you are standing near the edge of the top of a 200 feet building and throw a ball vertically upward it will be modeled by the function s(t)=-16t^2+64t+200 where s(t) is the ball's height above ground in feet and t is seconds after the ball was thrown. 
A) When does the ball reach its maximum height and what is the maximum height? 
T= -b/2a 
T= -64/-2(-16) 
T= 2 seconds 
How do I find the maximum height? 
B) When does the ball hit the ground? (Round to the nearest tenth of a second) 
Can you please help me with this question? 
C) Find s(0) and describe what it represents? 
Can you please help me with this question? 
D) How would I graph the quadratic function
Please help me solving each parts step by step!!!!

Reiny · Answer

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