freezing.
moles = grams/molar mass
Substitute and solve for moles NaCl.
molality = moles/kg solvent.
Substitute and solve for molality.
delta T = i*Kf*molality
Substitute and solve for delta T and convert to freezing point. i for NaCl = 2.
boiling point.
You can use the calculation above for moles; the work is already done.
You can use the calculation above for molality; the work is already done.
delta T = i*Kb*molality
Substitute and solve for delta T and convert to boiling point. i for NaCl = 2.
Post your work if you get stuck.
If you add 23.5g of NaCl to 1.2 kg of water, what will be the boiling point and the freezing point of the new solution? (Kf=1.86, Kb=0.52)
(Please show work, I appreciate everything)
1 answer