If you add 0.35grams NaF to 150mL of a 0.30M HF, what is the pH of the resulting solution?

Question

To start off would I use the value of 1.4e-11 for F^-^ and 7.2e-4 for HF?

Answer 1

This is a buffer problem.
pH = pKa + log(base)/(acid)
Use Ka for HF
Convert g NaF in 150 mL to M, then lug in the numbers.

Answer 2

So it would be pH=4.74 + log base/acid and I use 7.2e-4 for HF but after I convert g NaF in 150mL to M is this what I use for the base?