If y′= x(1+ y) and y > -1 , then y =

The differential equation dy/dx=y/x^2 has a solution given by:

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http://www.wolframalpha.com/input/?i=Solve++y%27(x)+%3D+x%2Bxy
dy/y = dx/x^2
ln y = -1/x + c
y = C e^-1/x

http://www.wolframalpha.com/input/?i=Solve++y%27(x)+%3Dy%2Fx%5E2
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dy/(1+y) = x dx
ln(1+y) = x^2/2
1+y = c e^(x^2/2)
y = c e^(x^2/2) - 1
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