dy/dx = x(1+y)
dy/(1+y) = x dx
ln(1+y) = 1/2 x^2 + ln(c)
1+y = c*e^(1/2 x^2)
it's starting to look like E to me.
if y' = x(1+y) and y > -1, then y =
a. y = C√(x+3)
b. y = 1/2 e^(x^2) + C
c. y = 3x^2 + C
d. y = sinx
e. y = Ce^(1/2x^2) -1
1 answer