y varies jointly as p and q ----> y = kpq
So that means that y/(pq) = k is constant.
(i) y/(12*15) = 8/(10*11)
(ii) 9/(7q) = 8/(10*11)
If y varies jointly as p and q and p=10 when q= 11 and y=8 (i)find y when q=12 and p=5.(ii)find q when y=9 and p=7
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