If y varies directly as x^2 and y=20 when x=4, find y when x=7?

3 answers

Y = kx^2 = 20. x = 4.
k*4^2 = 20.
16k = 20. k = 20/16 = 5/4.

Y = kx^2.
Y = (5/4)*7^2 = 61 1/4 = 61.25.
An investment of $63,000 was made by a business club. The investment was split into three parts and lasted one year. The first part of the investment earned 8% interest, the second 6% and the third 9%. Total interest from the investments was $4950. The interest from the investment was 4 times the interest from the second. Find totals of the three parts of the investment. What is the amount of the first part of the investment?
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