y = k * √w/x^3
The new y, y' will be
y' = k * √3w/(x/2)^3
= k * √3 * √w / (x^3/8)
= k * √w/x^3 * [√3 * 8]
= y * 8√3
If y varies directly as the square root of w and inversely as the cube of x, by what factor will y change if w is tripled and x is halved?
3 answers
I hate math
alebra is dum