If xΩy is defined as the smallest integer of which both x and y are factors, then 10Ω32 is how much greater than 6Ω20?

Answer 1

xΩy = LCM(x,y)
10Ω32 = LCM(10,32)=160
6Ω20=LCM(6,20)=60
can you take it from here?

Answer 2

Yes! Thanks!

Answer 3

You're welcome!

Answer 4

please explain in detail If xΩy is a least integer of which x and y are both factors than 10Ω132 is how much greater than 6Ω20

the answer of this was little bit complicated please explain