if x, 2x+1 and 3x-2 are GP with 4th term. find(a).x (b).common ratio (c).infinity
3 answers
I confused someone should help me surving this to me
I can not
not sure what "with 4th term" means, but
x = -3±√8
r = -1-√8
we need |r|<1, so the terms are
-3+√8, 4√2-5, 6√2-11
S = a/(1-r) = (√8-3)/(√8+2) = (7-5√2)/2
why do I suspect a typo?
x = -3±√8
r = -1-√8
we need |r|<1, so the terms are
-3+√8, 4√2-5, 6√2-11
S = a/(1-r) = (√8-3)/(√8+2) = (7-5√2)/2
why do I suspect a typo?
2 answers