To find the sine ratio for angle \( g \) in triangle ACB where angle C is a right angle, we can use the definition of the sine function for a right triangle:
\[ \sin(g) = \frac{\text{opposite}}{\text{hypotenuse}} \]
In this scenario:
- The segment opposite to angle B (which measures \( g \) degrees) is segment AC, which has a length of \( x = 10 \).
- The hypotenuse of the triangle is segment AB, which has a length of \( z = 11 \).
Now we can substitute these values into the sine ratio:
\[ \sin(g) = \frac{AC}{AB} = \frac{x}{z} = \frac{10}{11} \]
Since we need to determine which of the options given corresponds to this value, we see that:
- The options provided are:
- one half
- 2 over 1
- ten elevenths
- five elevenths
The sine ratio we calculated, \( \frac{10}{11} \), matches the option "ten elevenths."
Thus, the answer is: ten elevenths.
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