2g CO2 x (atomic mass C/molarmass CO2) = approx 0.6 mols C
6.02E21/6.02E23 = 0.01 mols N
0.03 mols O
but that isn't 5:1:3 but more like 60:1:3
If we take 2.2 grams of CO2, 6.02 X 1021 atomes of nitrogen and 0.03 gram atoms of sulphar , then the molar ratio of C, N, and O is .
answer is 5:1 :3
how to solve it help please , thanks
9 answers
@DrBob222 , thanks for reply, thanks sir
Sorry but I made an error above in the conversions and the 5:1:3 IS right after all.
mols CO2 = g/molar mass = 2.2/44 = 0.05. I convert to grams C which isn't right. mols C is the same as mols CO2; therefore, we have
mols C = 0.05
mols N = 0.01
mols O = 0.03
and the ratio is C5NO3
mols CO2 = g/molar mass = 2.2/44 = 0.05. I convert to grams C which isn't right. mols C is the same as mols CO2; therefore, we have
mols C = 0.05
mols N = 0.01
mols O = 0.03
and the ratio is C5NO3
@DrBob222 , Thanks sir, but I still cant understand , help me out,
see , 2.2g X 12/44 = 0.6 moles of CO2, so how to calculate Moles of N and O ?
see , 2.2g X 12/44 = 0.6 moles of CO2, so how to calculate Moles of N and O ?
If 0.03 gram atoms of sulfur is given then why ratio of oxygen is asked.....so basicaly there is error in question ratio of Sulfur should be asked instead of Oxygen so
Moles of C=0.05
Moles of N=6.02x10^21/6.02x10^23=0.01
Moles of S=0.03 (1gram atoms = 1mole)
So Ratio is 5:1:3
Moles of C=0.05
Moles of N=6.02x10^21/6.02x10^23=0.01
Moles of S=0.03 (1gram atoms = 1mole)
So Ratio is 5:1:3
How can we find moles of oxygen? Plz answer: DrBob222 , Shahab Mirza
How did u calculate the moles of sulphur .. plz help!
It's already given
How to calculate moles for O by this data? Please answer it.
1 answer