The stoichiometric amount of NaCl is the theoretical yield.
Convert 25 NaBr to moles. moles = grams/molar mass.
Using the coefficients in the balanced equation, convert moles NaBr to moles NaCl.
Now convert moles NaCl to grams. g = moles x molar mass. This is the theoretical yield.
NOTE: I assume you made up this problem to demonstrate theoretical yield and I have worked the problem accordingly. However, the reaction, in real practice, will NOT take place.
if we mix 25 g of sodium bromide with a large amount of potassium chloride, what will our theoretical yield of sodium chloride be?
NaBr+KCL->NaCl+KBr
how do you calculate theoretical yield?
5 answers
soooo...would it be like this?
25gx 1mol/103g = 0.2427...
ans.x58
theoretical yield =14.0g
25gx 1mol/103g = 0.2427...
ans.x58
theoretical yield =14.0g
Yes and no.
Yes, the answer is 14 however, you have mixed up the number of significant figures. If you start with 25 g, the answer may not have more than two; therefore, 14 g is the answer in your problem.
Yes, the answer is 14 however, you have mixed up the number of significant figures. If you start with 25 g, the answer may not have more than two; therefore, 14 g is the answer in your problem.
Why did you time is by 58? like where did the 58 come from
14.2gNaCl