If we know that the definite integral from -6 to -3 of f(x) equals 6, the definite integral from -6 to -5 equals 2 and the definite integral from -4 to -3 equals 4 then:
What is the definite integral from -5 to -4? I know that this is zero.
But then what can we say about the definite integral from -4 to -5 of not just f(x) but 6f(x)-2?
i'm lost! I thought it would just be zero... Thank you!
1 answer
Nevermind guys I got It!!!