It seems there is a slight error in the equation you provided. The use of both "="- and "+" appears to be incorrect. Assuming you meant a linear equation in slope-intercept form \(y = mx + b\), let’s clarify your original equation.
If we correct it as:
- Original equation: \(y = -0.14x + 3\)
Now, if we change the 3 to a 0, the equation becomes:
- New equation: \(y = -0.14x + 0\) or simply \(y = -0.14x\)
Changes to the Graph:
-
Y-Intercept:
- The original equation has a y-intercept of 3 (where the line crosses the y-axis).
- The new equation has a y-intercept of 0 (where the line now crosses the y-axis at the origin).
-
Slope:
- The slope, -0.14, remains unchanged, meaning the direction and steepness of the line stay the same.
Summary of Graphical Changes:
- The line would shift downward, moving from being positioned higher with a y-intercept of 3 to passing through the origin (0,0) with a y-intercept of 0.
- The overall slope of the line will remain constant, but its vertical position on the graph will change.
So, to sum up, changing the y-intercept from 3 to 0 shifts the entire line down to cross the y-axis at the origin, while maintaining the same slope.