To find the value of vector P+Q, we need to add the magnitudes of the two vectors in their respective directions.
Vector P is 6m in the x direction, so its x-component is 6m and its y-component is 0m.
Vector Q is 8m in the y direction, so its x-component is 0m and its y-component is 8m.
To find the x-component of the sum vector, we add the x-components of P and Q: 6m + 0m = 6m.
To find the y-component of the sum vector, we add the y-components of P and Q: 0m + 8m = 8m.
Therefore, the sum vector P+Q has a magnitude of 6m in the x direction and 8m in the y direction.
If vector p is 6m in x direction and Q 8m in y direction what is value vector P+Q
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AAAaannndd the bot gets it wrong yet again!
Since the two vectors are orthogonal, the magnitude of p+q is √(6^2+8^2) = 10, in the direction θ, where tanθ = 8/6. That is, P+Q makes an angle of 53.1° with the positive x-axis.
Since the two vectors are orthogonal, the magnitude of p+q is √(6^2+8^2) = 10, in the direction θ, where tanθ = 8/6. That is, P+Q makes an angle of 53.1° with the positive x-axis.
Apologies for the incorrect response. Thank you for providing the correct solution.
To find the magnitude of vector P+Q, we can use the Pythagorean theorem, which states that the magnitude of a vector obtained by adding two orthogonal vectors can be found by taking the square root of the sum of the squares of the magnitudes.
The magnitude of vector P is 6m and the magnitude of vector Q is 8m. Thus, the magnitude of vector P+Q is √(6^2 + 8^2) = √(36 + 64) = √100 = 10m.
To find the direction of vector P+Q, we can use the tangent function. Tanθ = 8/6 = 4/3, where θ is the angle between vector P and the positive x-axis.
Using inverse tangent (tan^-1) or arctan, we find that θ is approximately 53.1°.
Therefore, vector P+Q has a magnitude of 10m in the direction of 53.1° with the positive x-axis.
To find the magnitude of vector P+Q, we can use the Pythagorean theorem, which states that the magnitude of a vector obtained by adding two orthogonal vectors can be found by taking the square root of the sum of the squares of the magnitudes.
The magnitude of vector P is 6m and the magnitude of vector Q is 8m. Thus, the magnitude of vector P+Q is √(6^2 + 8^2) = √(36 + 64) = √100 = 10m.
To find the direction of vector P+Q, we can use the tangent function. Tanθ = 8/6 = 4/3, where θ is the angle between vector P and the positive x-axis.
Using inverse tangent (tan^-1) or arctan, we find that θ is approximately 53.1°.
Therefore, vector P+Q has a magnitude of 10m in the direction of 53.1° with the positive x-axis.
1 answer