Let the triangle be ABC, and where the medians AD and BE intersect be M.
The three medians intersect at the centroid, and divide each other in the ratio 1:2
That means that AM = BM and the triangle ABM is isosceles.
If two medians of a triangle are equal, prove that the triangle formed by a segment of each median and the third side is an isosceles triangle.
2 answers
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