sum of 2 : 1 --(1,1)
sum of 3 : 2 -- (1,2) (2,1)
sum of 4 : 3 -- (1,3) (3,1) (2,2)
So sum of 4 or less : 6 of them
Then the number of tosses with a sum greater than 4 is 30 (there are 36 possible cases)
prob(of your event) = 30/36 = 5/6
if two fair dice are rolled what is the probability that the total showing is more than four?
Will you please explain how to do this problem?
Thank you
1 answer