Question

if two fair dice are rolled what is the probability that the total showing is more than four?

Will you please explain how to do this problem?

Thank you

Answer 1

sum of 2 : 1 --(1,1)
sum of 3 : 2 -- (1,2) (2,1)
sum of 4 : 3 -- (1,3) (3,1) (2,2)

So sum of 4 or less : 6 of them
Then the number of tosses with a sum greater than 4 is 30 (there are 36 possible cases)

prob(of your event) = 30/36 = 5/6