If two buses are needed to transport 75 students to the aquarium and eight buses can transport 300 students to the aquarium, which proportion describes the relationship between the number of buses, and the number of students do not reduce the ratios to their lowest terms

Answer 1

Let's define:
b = number of buses
s = number of students

We know that the relationship between the number of buses and the number of students is given by the ratio of 8 buses to 300 students. So, we can write:

8 buses/300 students = b buses/s students

To find the relationship between the number of buses and the number of students needed to transport 75 students, we can solve for b. Rearranging the equation, we have:

b buses = (8 buses/300 students) * (s students)

We have the information that two buses are needed to transport 75 students, so we can substitute b = 2 buses and s = 75 students:

2 buses = (8 buses/300 students) * (75 students)

Now we can solve for (75 students) by multiplying both sides of the equation by (300 students/8 buses), canceling out units on the right side:

2 buses * (300 students/8 buses) = (75 students)

Simplifying the right side, we get:

2 buses * 37.5 students/bus = 75 students

So, the proportion that describes the relationship between the number of buses and the number of students is:

2 buses : 75 students