To determine the number of grams of CO2 gas produced, we need to first determine the number of moles of HCl in the solution, and then use stoichiometry to convert the moles of HCl to moles of CO2 gas, and finally convert to grams of CO2 gas using the molar mass of CO2.
The balanced chemical equation for the reaction between HCl and CaCO3 is:
2HCl + CaCO3 -> CaCl2 + CO2 + H2O
From the equation, we can see that 2 moles of HCl react with 1 mole of CaCO3 to produce 1 mole of CO2 gas.
First, let's calculate the number of moles of HCl in the solution:
Moles of HCl = concentration of HCl x volume of solution
Moles of HCl = 0.300 mol/L x 0.0250 L
Moles of HCl = 0.0075 mol
According to the stoichiometry of the balanced equation, we know that 2 moles of HCl react with 1 mole of CaCO3 to produce 1 mole of CO2 gas, so the number of moles of CO2 gas produced is also 0.0075 mol.
Lastly, let's convert moles of CO2 gas to grams of CO2 gas using the molar mass of CO2:
Molar mass of CO2 = (12.01 g/mol) + (2 * 16.00 g/mol)
Molar mass of CO2 = 44.01 g/mol
Grams of CO2 gas = moles of CO2 gas x molar mass of CO2
Grams of CO2 gas = 0.0075 mol x 44.01 g/mol
Grams of CO2 gas = 0.3308 g
Therefore, approximately 0.3308 grams of CO2 gas are produced.
If Tums (CaCO3) is added to 25.0 mL of a solution that is 0.300 M in HCl, how many grams of CO2 gas are produced?
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