If Tom kicks a 0.350 kg soccer ball with 0.90 N of force, what is the acceleration of the ball?

F= ma

a
0.32 m/s2

b
315 m/s2

c
2.6 m/s2

d
0.003 m/s2

e
388.9 m/s2

f
3.15 m/s2

1 answer

To find the acceleration of the soccer ball, we can use Newton's second law, which states that \( F = ma \), where \( F \) is the force applied, \( m \) is the mass of the object, and \( a \) is the acceleration.

We can rearrange the formula to solve for acceleration \( a \):

\[ a = \frac{F}{m} \]

Given:

  • \( F = 0.90 , \text{N} \)
  • \( m = 0.350 , \text{kg} \)

Now, we can plug in the values:

\[ a = \frac{0.90 , \text{N}}{0.350 , \text{kg}} \approx 2.57 , \text{m/s}^2 \]

Rounding this to two decimal places gives us approximately \( 2.6 , \text{m/s}^2 \).

Thus, the correct answer is:

c 2.6 m/s².