Did you notice that 6^2 + 8^2 = 10^2, so you have a right-angled triangle.
Sketch that triangle ABC, so that AB=8 , BC=6 and AC = 10
draw the altitude BD, where D is on AC
label angles A and C as x and y. Yous should notice that you have
3 similar triangles and we can use ratios to find BD
Using ABC and BDC
BD/8 = 6/10
BD = 48/10 = 4.8
if three sides of a triangle are 6cm ,8cm and 10cm then find the altitude of the triangle using the largest side as base....
really need help with this question
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