The formula for the relationship between frequency, wavelength, and speed is:
\(v = f \times \lambda\)
Where:
\(v\) = speed of the wave
\(f\) = frequency of the wave
\(\lambda\) = wavelength of the wave
If the speed remains constant at 600 m/s and the wavelength is increased to 10m, we can rearrange the formula to solve for the new frequency:
\(f = v / \lambda\)
Plugging in the values, we get:
\(f = 600 / 10\)
\(f = 60\)
Therefore, the frequency of the wave would decrease to 60 Hz if the wavelength is increased to 10m while the speed remains at 600 m/s.
If the wavelength is increased to 10m while the speed remains at 600 m/s, the frequency of the wave would decrease to 60 Hz. This is because frequency and wavelength are inversely proportional to each other when speed is held constant.
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