if the volume of the vapor had been assumed to be 125ml instead of your measured volume,what would have been the percent error in your report? molar mass of the compound?explain

Answer 1

Let's assume that in the experiment, you have a measured volume V_measured and calculated the molar mass MM_measured based on that. Now, we are given a different volume V_assumed = 125 ml, and we need to find out what the molar mass based on this assumed volume would have been (MM_assumed).

To calculate this, we would need more information about the experiment, such as the mass of the compound, temperature, pressure, and any other relevant factors in the experiment.

Once we have the required information, we can use the ideal gas law:

PV = nRT

Where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature

Using the stoichiometry of the reaction and the given mass of the compound, we can calculate the number of moles (n) and use this to calculate molar mass (MM).

For the measured volume:

n = PV / (RT) => MM_measured = (mass) / (PV_measured / RT)

For the assumed volume:

n = PV / (RT) => MM_assumed = (mass) / (PV_assumed / RT)

Now, we have MM_measured and MM_assumed. To calculate the percent error in molar mass:

Percent error = ((MM_measured - MM_assumed) / MM_measured) * 100

This will give you the percent error in your report on the molar mass of the compound with the assumed volume instead of the measured volume.