If the unknown tri protic acid has an equivalent weight of 139.42 g/equiv, its average molecular weight is
_________g/mol and __________g would be required to make 100.00 mL of a 1.50 N solution.
See my response to your first question.
_________g/mol and __________g would be required to make 100.00 mL of a 1.50 N solution.
See my response to your first question.