if the tv us 60inchs and the height is 30 inchs what is the width in inchs?

Answer 1

To find the width of the TV, we can use the Pythagorean theorem:

width^2 + height^2 = diagonal^2

Let's denote the width as 'w' and the diagonal as 'd':

w^2 + 30^2 = 60^2

Simplifying the equation:

w^2 + 900 = 3600

Subtracting 900 from both sides:

w^2 = 2700

Taking the square root of both sides:

w = √2700

w ≈ 51.96

Therefore, the width of the TV is approximately 51.96 inches.

Answer 2

if the tv us 52 inchs and the width is 45 inchs? inchs what is the hight in inchs?

Answer 3

To find the height of the TV, we already know the width and diagonal. We can use the Pythagorean theorem:

height^2 = diagonal^2 - width^2

Let's denote the height as 'h' and the diagonal as 'd':

h^2 = 52^2 - 45^2

Simplifying the equation:

h^2 = 2704 - 2025

h^2 = 679

Taking the square root of both sides:

h = √679

h ≈ 26.06

Therefore, the height of the TV is approximately 26.06 inches.

Answer 4

if the height is 20 inchs and the width is 35 what if the over all inches?

Answer 5

To find the overall size of the TV, we can use the formula for calculating the diagonal length of a rectangle:

diagonal^2 = height^2 + width^2

Let's denote the diagonal as 'd':

d^2 = 20^2 + 35^2

Simplifying the equation:

d^2 = 400 + 1225

d^2 = 1625

Taking the square root of both sides:

d = √1625

d ≈ 40.31

Therefore, the overall size (diagonal length) of the TV is approximately 40.31 inches.