Asked by Unknown
If the true velocity of a rocket is 711 m/s, which of the following measurements taken on that velocity would be the most accurate?
answers:
v = 502.8 m/s
v= 502.8 m/s
v= 681.7 m/s
v= 707.9 m/s
answers:
v = 502.8 m/s
v= 502.8 m/s
v= 681.7 m/s
v= 707.9 m/s
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To determine which measurement is the most accurate compared to the true velocity of the rocket (711 m/s), we need to calculate the absolute differences between the true velocity and each of the provided measurements.
1. For \(v = 502.8\) m/s:
\[
|711 - 502.8| = 208.2 \text{ m/s}
\]
2. For \(v = 502.8\) m/s (duplicate):
\[
|711 - 502.8| = 208.2 \text{ m/s}
\]
3. For \(v = 681.7\) m/s:
\[
|711 - 681.7| = 29.3 \text{ m/s}
\]
4. For \(v = 707.9\) m/s:
\[
|711 - 707.9| = 3.1 \text{ m/s}
\]
Now we compare the absolute differences:
- \(v = 502.8\) m/s: 208.2 m/s
- \(v = 502.8\) m/s: 208.2 m/s
- \(v = 681.7\) m/s: 29.3 m/s
- \(v = 707.9\) m/s: 3.1 m/s
The smallest difference is for \(v = 707.9\) m/s, which is 3.1 m/s away from the true velocity of 711 m/s.
Thus, the most accurate measurement is **v = 707.9 m/s**.
1. For \(v = 502.8\) m/s:
\[
|711 - 502.8| = 208.2 \text{ m/s}
\]
2. For \(v = 502.8\) m/s (duplicate):
\[
|711 - 502.8| = 208.2 \text{ m/s}
\]
3. For \(v = 681.7\) m/s:
\[
|711 - 681.7| = 29.3 \text{ m/s}
\]
4. For \(v = 707.9\) m/s:
\[
|711 - 707.9| = 3.1 \text{ m/s}
\]
Now we compare the absolute differences:
- \(v = 502.8\) m/s: 208.2 m/s
- \(v = 502.8\) m/s: 208.2 m/s
- \(v = 681.7\) m/s: 29.3 m/s
- \(v = 707.9\) m/s: 3.1 m/s
The smallest difference is for \(v = 707.9\) m/s, which is 3.1 m/s away from the true velocity of 711 m/s.
Thus, the most accurate measurement is **v = 707.9 m/s**.
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