If the total positive charge is Q = 1.62×10−6C , what is the magnitude of the electric field caused by this charge at point P, a distance d = 1.53m from the charge? (Figure 1)

Question

If the total positive charge is Q  = 1.62×10−6C  , what is the magnitude of the electric field caused by this charge at point P, a distance d  = 1.53m  from the charge? (Figure 1)

Enter your answer numerically in newtons per coulomb.

Damon · Answer

E = k Q/r^2 direction away from Q since Q is positive