To find the height of the net diagram of the right circular cylinder, we first need to find the radius of the cylinder.
The surface area of a right circular cylinder can be calculated using the formula:
Surface Area = 2πr(h + r)
Given that the surface area is 395.64 feet and using 3.14 for π, we can set up the equation as follows:
395.64 = 2 * 3.14 * r * (h + r)
Since there is a small "2" at the top of the cylinder, it indicates that the net diagram includes the two circular faces of the cylinder. Therefore, the net diagram includes two circles, each having an area equal to πr^2.
Subtracting the area of these two circles from the total surface area gives us the lateral surface area:
395.64 - (2 * 3.14 * r^2) = 2 * 3.14 * r * h
395.64 - 6.28r = 6.28rh
Now, if we plug in the radius and circumference formula in the second equation,
395.64 - 6.28(395.64/6.28) = 6.28 * (395.64/6.28) * h
395.64 - 395.64 = 395.64h
h = 0 feet
Therefore, the height of the net diagram is 0 feet.
If the surface area of the net diagram of the right circular cylinder is 395.64 feet with a small two at the top find a height of the net diagram using 3.14 for Tt
1 answer
1 answer