To calculate the surface area of a square pyramid, we need to find the areas of the four triangular faces and the base.
Given:
Area of square pyramid = 65 ft^2
Area of the four triangular faces = 40 ft^2
Let x be the length of one side of the square base of the pyramid.
Since the base is a square, the area of the base = x^2
The total surface area of the pyramid is the sum of the area of the base and the area of the four triangular faces:
65 ft^2 = 40 ft^2 + x^2
Therefore,
x^2 = 65 ft^2 - 40 ft^2
x^2 = 25 ft^2
Taking the square root of both sides:
x = 5 ft
Therefore, the length of one side of the square base of the pyramid is 5 ft.
If the surface area of a square pyramid is 65ft squared and the areas of the four triangular faces is 40ft squared what is the length of one of the sides
1 answer