If the sum of two numbers is 30 and their difference is 8. What is their product?

1 answer

Let the two numbers be \( x \) and \( y \).

We are given the following two equations based on the problem statement:

  1. \( x + y = 30 \)
  2. \( x - y = 8 \)

To solve for \( x \) and \( y \), we can add the two equations together:

\[ (x + y) + (x - y) = 30 + 8 \]

This simplifies to:

\[ 2x = 38 \]

Now, divide both sides by 2:

\[ x = 19 \]

Next, we can substitute \( x = 19 \) back into the first equation to find \( y \):

\[ 19 + y = 30 \]

Subtracting 19 from both sides gives:

\[ y = 30 - 19 = 11 \]

Now that we have both numbers, \( x = 19 \) and \( y = 11 \), we can find their product:

\[ x \times y = 19 \times 11 \]

Calculating the product:

\[ 19 \times 11 = 209 \]

Thus, the product of the two numbers is \( \boxed{209} \).