If the solubility constant for Ag2CO3 is equal to 8.1x10^-12 how many grams of Ag2CO3 will dissolve in a .0001 M solution of Na2CO3?

Answer 1

.....Ag2CO3 ==< 2Ag^+ + CO3^2-
I.....solid......0.....0.0001
C.....solid......2x.......x
E.....solid......2x...0.0001+x

Subsitute the E line into the Ksp epxression and solve for x = solubility in M. Then grams = mols x molar mass