In an isosceles triangle, two angles are equal in size. Let's call the size of these two angles x.
We know that the smallest angle is 36°, so one of the equal angles is 36°.
Therefore, we have:
x + x + 36° = 180° (the sum of the angles in a triangle)
2x + 36° = 180°
2x = 144°
x = 144°/2
x = 72°
So, each of the other two larger angles is 72°.
If the smallest angle in an isosceles triangle is 36°, what is the size of each of the other two larger angles?
1 answer