If the side opposite a 60-degree angle in a 30-60-90 right triangle is 73–√ cm long, how long is the hypotenuse?(1 point)

Responses

73–√ cm
7 Start Root 3 End Root cm

14 cm
14 cm

28 cm
28 cm

7 cm

1 answer

In a 30-60-90 triangle, the ratios of the lengths of the sides are as follows:

  • The side opposite the 30-degree angle (shorter leg) is \( x \).
  • The side opposite the 60-degree angle (longer leg) is \( x\sqrt{3} \).
  • The hypotenuse is \( 2x \).

Given that the side opposite the 60-degree angle is \( 73 - \sqrt{cm} \), we can set this equal to \( x\sqrt{3} \):

\[ x\sqrt{3} = 73 - \sqrt{cm} \]

To find \( x \), we divide both sides by \( \sqrt{3} \):

\[ x = \frac{73 - \sqrt{cm}}{\sqrt{3}} \]

Now, to find the hypotenuse, we use the formula \( 2x \):

\[ \text{Hypotenuse} = 2x = 2 \left( \frac{73 - \sqrt{cm}}{\sqrt{3}} \right) = \frac{2(73 - \sqrt{cm})}{\sqrt{3}} \]

Next, let's evaluate the choices given:

  1. 73–√ cm
  2. 7√3 cm
  3. 14 cm
  4. 28 cm
  5. 7 cm

To proceed, we need numerical values, so let's approximate.

Noting the options, if \( 73 - \sqrt{cm} = 14 \) (the option might be derived from some numerical example), we can:

\[ \sqrt{cm} = 73 - 14 = 59 \] Now substituting back to find \( x \):

\[ x\sqrt{3} = 14 \implies x = \frac{14}{\sqrt{3}} \implies \text{Hypotenuse} = 2x = 2 \cdot \frac{14}{\sqrt{3}} = \frac{28}{\sqrt{3}} \text{which does not match.} \]

Try for hypotenuse possibilities:

For \( 73 - \sqrt{cm} \) to match with given options, if we assume \( \sqrt{cm} \) contributes to 7, \( x\) gives us even numbers diverging.

However, checking a common setup for \( x\), trying quick values:

  1. For \( 14 \) we took: \[ 14 = x\sqrt{3} \ x=\frac{14}{\sqrt{3}} \implies Hypotenuse = 28 \]

So, the answer is 28 cm as per the evaluation or merits of provided choices.

28 cm would indeed be correct given the relationships on a 30-60-90 triangle study.

So from the options provided, the answer is:

28 cm.