If the side opposite a 60-degree angle in a 30-60-90 right triangle is 7sqrt3 cm long, how long is the hypotenuse?

1 answer

In a 30-60-90 triangle, the lengths of the sides are in a specific ratio:

  • The side opposite the 30-degree angle (let's call it \( x \))
  • The side opposite the 60-degree angle (which is \( \sqrt{3} \times x \))
  • The hypotenuse (which is \( 2 \times x \))

You mentioned that the side opposite the 60-degree angle is \( 7\sqrt{3} \) cm long. According to the properties of 30-60-90 triangles, we can set up the relationship as follows:

\[ \text{Side opposite 60 degrees} = \sqrt{3} \times x \]

Substituting the given value:

\[ \sqrt{3} \times x = 7\sqrt{3} \]

To find \( x \), we divide both sides by \( \sqrt{3} \):

\[ x = 7 \]

Now, we can find the length of the hypotenuse using the relationship \( 2 \times x \):

\[ \text{Hypotenuse} = 2 \times x = 2 \times 7 = 14 \]

Therefore, the length of the hypotenuse is \( \boxed{14} \) cm.