no, multiplying by 3 does not change the roots. For, you have
3ax^2+3bx+3c = 3(ax^2+bx+c) = 0
If the roots of ax^2+bx+c=0 are 6 and 9, then the roots of 3ax^2+3bx+3c=0 are
A. 2 and 3
B. 6 and 9
C. 18 and 27
D. -2 and -3
I think since you multiply by 3, the roots are multiplied by 3, but I'm not sure.
2 answers
So would it be 6 and 9 again?