If the rectangles width is trippled and its length is doubled the perimeter of the new rectangle is 92 centimeter greater than the original perimeter what is the area of the original rectangle?

Answer 1

original perimeter = 2L + 2w

new length = 2L
new width = 3W

new perimeter = 4L + 6w

4L+6w - (2L+2w) = 92
2L + 4w = 92
L + 2w = 46
L = 46-2w

area of original = lw
= w(46-2w)
= 46w - 2w^2