To find the current price of the item, we can plug \( t = 0 \) into the function \( p(t) = 800(1.037)^t \).
Current Price:
\[ p(0) = 800(1.037)^0 = 800(1) = 800 \] So, the current price of the item is $800.
Price 10 Years from Today:
Now, we will find the price 10 years from today by plugging \( t = 10 \) into the function.
\[ p(10) = 800(1.037)^{10} \]
Calculating \( 1.037^{10} \): \[ 1.037^{10} \approx 1.4107 \]
Now, calculate \( p(10) \): \[ p(10) \approx 800 \times 1.4107 \approx 1128.56 \]
Rounding to the nearest dollar: \[ p(10) \approx 1129 \]
Final Answers:
- Current price: $800
- Price 10 years from today: $1129