if the radius and height of a cone both are increased by 10%. how much is the volume increased.

Answer 1

old radius -- x
old height -- h
old volume = (1/3)πr^2 h

new radius = 1.1r
new height = 1.1h
new volume = (1/3)π (1.1r)^2 (1.1)h
= 1.1^3 (1/3)πr^2 h

ratio of increase = 1.1^3 (1/3)πr^2 h/((1/3)πr^2 h)
= 1.1^3 = 1.331
there is a 33.1% increase

Answer 2

The last ans we get is 1.331 and then how do we get 33.1%

Answer 3

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