P = kQ^2/√R
so, P√R/Q^2 = k, which is constant.
So, you want to find P such that
P√25/1^2 = 12√81/3^2
now just simplify and solve for P
If the quantity P varies as the square of Q and inversely as the square root R. If P=12,Q=3 and R=81,find P if Q=1 and R°25
1 answer