If the polynomial x^3+6x^2+11x+6 expresses the volume, in cubic inches, of the box, and the width is (x+1)in., what are the dimensions of the box?
I need to answer the question in long dvision or synthetic division, the thing is i have no idea how to do either of those.
quick explanation?
2 answers
Am i capable of taking this question down? no one answered and ive gotten the information i needed from other sources.
a little synthetic division quickly shows that
x^3+6x^2+11x+6 = (x+1)(x^2+5x+6) = (x+1)(x+2)(x+3)
x^3+6x^2+11x+6 = (x+1)(x^2+5x+6) = (x+1)(x+2)(x+3)
1 answer