First, we need to calculate the maximum output voltage that the op-amp can produce before reaching the saturation limit:
Vsat = ±13V
Next, we need to calculate the gain of the inverting amplifier:
G = -RC/RA = -40
We can convert this to dB to find the voltage gain in decibels:
GdB = 20*log10(G) = 32.0dB
Now we can find the output voltage for a given input voltage:
Voutpp = Vin*G = 0.5*G = 0.5*(-40) = -20Vpp
However, this exceeds the op-amp's saturation limit, so the maximum output voltage will be limited to:
Voutpp_max = Vsat/G = 13/40 = 0.325Vpp
Therefore, the maximum output voltage of the inverting amplifier is 0.325Vpp.
If the output saturation voltage of the op-amp is ± 13V, determine Voutpp in inverting amplifier.
ACL = -40
ACL in dB = 32.0dB
RA = 500Ω
RC = 20KΩ
VIN = 0.5 Vpp
3 answers
Describe the output voltage.
The output voltage of the inverting amplifier will vary linearly with the input voltage, but with a negative gain (amplification factor) determined by the ratio of the feedback resistor (RF) to the input resistor (RIN). In this case, the gain is -40, so for a given input voltage amplitude, the output voltage amplitude will be 40 times smaller. However, in practical situations, the output voltage may be limited by the saturation voltage of the op-amp if the input signal is too large. In this case, the maximum output voltage is limited to ±13V.