If the nth term of a sequence Is given by 2*3^n-2, find the first three term of the sequence

Answer 1

To find the first three terms of the sequence, we plug in n=1, n=2, and n=3 into the given nth term formula and simplify:

- When n=1: 2*3^(1-2) = 2*3^-1 = 2/3
- When n=2: 2*3^(2-2) = 2*3^0 = 2
- When n=3: 2*3^(3-2) = 2*3^1 = 6

Therefore, the first three terms of the sequence are 2/3, 2, and 6.