If the nth partial sum of

Question

an is sn=(3n-2)/(n+1)

what is an when x>1?
and what is the sum of an?

Answer 1

I assume that Sn = sum(1..n) An, so Sn -> 3

Dunno where the x comes from, but if you mean when n > 1,

An = Sn - s(n-1)
= (3n-2)/(n+1) - (3(n-1)-2)/(n-1+1)
= 5 / n(n+1)