M = mols/L
0.0013 M = mols/3.50L
mols = 0.0013 mols/L x 3.50L = estimated 0.005 mols but you need to do that more accurately.
Then substitute for n in PV = nRT with other conditions and solve for volume.
If the methane contained in 3.50L of a saturated solution at 25 ∘C was extracted and placed under STP conditions, what volume would it occupy?
Solubility of methane is 1.3 millimolar
1 answer